Calculation of cable current carrying capacity | How to calculate the current carrying capacity of three-phase cables

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How to calculate the current carrying capacity of a 1.10kV cable? How to calculate the current carrying capacity of a 10kV cable? Firstly, the maximum current carrying capacity of a cable can be calculated by multiplying its cross-sectional area (in mm ²) by the maximum current density allowed by the cable material (in A/mm ²). The current density depends on the material of the cable. For example, the current carrying capacity of copper wire is usually 5-8 A/mm ², while that of aluminum wire is 3-5 A/mm ². For example, for a 2.5 mm ² BVV copper wire, the recommended safe current carrying capacity is 2.5 × 8A/mm ²=20A. Similarly, the recommended safe current carrying capacity for a 4 mm ² BVV copper wire is 4 × 8A/mm ²=32A. The cross-sectional area of copper wire can be calculated based on its recommended safe current carrying capacity (5~8A/mm ²), and the upper and lower range of the cross-sectional area S can be determined as S=I/(5~8)>=0.125 I~0.2 I (mm ²). Here, I represents the load current (unit: A). In terms of power calculation, the calculation formula for resistive loads is P=UI, while the calculation formula for fluorescent lamp loads is P=UIcos φ, where the power factor cos φ of the fluorescent lamp load is 0.5. The power factor of different inductive loads varies, and household appliances can usually calculate the power factor cos φ uniformly by taking 0.8. For example, if the total power of all appliances in a household is 6000 watts and a common factor of 0.8 is taken, the maximum current I=P/(Ucos φ)=6000 × 0.8/(220 × 0.8)=17A. This means that the total current value of the household is 17A, so the total number of gates for air switches cannot be 16A and should be greater than 17A. Finally, it should be
Calculation of cable current carrying capacity
pointed out that due to its high insulation level, thick external film, and inferior heat dissipation compared to low-voltage cables, high-voltage cables with the same cross-sectional area have slightly lower current carrying capacity than ordinary cables.

2. How to calculate the current carrying capacity of a three-phase cable

The calculation method for the current carrying capacity of a three-phase cable is as follows

1. According to the formula for calculating the three-phase electrical phase line current: I=P ÷ (U × 1.732 × cos Φ), where P is power (unit: watt), U is voltage (unit: volt), cos Φ is power factor (usually taken at 0.85), and I is phase line current (unit: ampere).

. For example, assuming the motor power P=7.5 kW, voltage U=380 volts, and power factor cos Φ=0.85, the phase line current I=13.3 amperes. In a three-phase balanced circuit, the safe current carrying capacity of copper wires is generally 5 to 8 amperes per square millimeter. According to the above calculation, the phase line current I=13.3 amperes, and the required cross-sectional area of the wire A=I ÷ 8=1.66 square millimeters, the closest cable specification is 2.5 square millimeters. Additional information: The purpose of cable current carrying capacity is to transmit electrical energy. The calculation formula for three-phase electrical power is: P=1.732UIcos φ, where P is the electrical power (in kilowatts), U is the voltage (in kilovolts), I is the current (in amperes), and cos φ is the natural power factor of the system. To transmit electrical energy, there must be current flowing through the circuit. The larger the current passing through the line, the more electrical power is transmitted. Current carrying capa

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